Files
lec-sdr/a5.md
eneller 876c00011e a5/a6
2026-04-07 01:30:59 +02:00

1.1 KiB

Suppressed Carrier Wave

Derive expressions from which it will be evident whether the communication channel has more power as an AM signal with a suppressed carrier wave or as an AM signal with the carrier wave present. Assume the voltage signal, v(t) and m(t), as in the previous figure. Modulating (LF) sinusoidal signal has amplitude A and frequency f_{LF} Hz, cosine wave RF carrier has amplitude 1 and frequency f_{VF}.

According to P_t = P_c + P_{USB} + P_{LSB} the total transmitting power has to be split among carrier, upper and lower side band. With the carrier wave suppressed, the modulating signal will take up all of the available transmission power instead.

For a standard AM signal with the above requirements, the formula is:

s(t) = (1+A \cos(2\pi f_{LF}t)) \cdot \cos(2\pi f_{VF} t)

With the power of a wave signal given by P=\frac{(v_m/\sqrt{2})^2}{2} (where v_m is max of cosine signal), our sideband power is 2* \frac{(A/\sqrt{2})^2}{2} = \frac{A^2}{2} and our carrier power \frac{1}{2}, equal to the power gained in DSB-SC.