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# Suppressed Carrier Wave
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Derive expressions from which it will be evident whether the
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communication channel has more power as an AM signal with
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a suppressed carrier wave or as an AM signal with the carrier
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wave present. Assume the voltage signal, $v(t)$ and $m(t)$, as in
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the previous figure. Modulating (LF) sinusoidal signal has
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amplitude $A$ and frequency $f_{LF}$ Hz, cosine wave RF carrier has
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amplitude $1$ and frequency $f_{VF}$.
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According to $P_t = P_c + P_{USB} + P_{LSB} $ the total transmitting power has to be split among carrier, upper and lower side band.
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With the carrier wave suppressed, the modulating signal will take up all of the available transmission power instead.
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For a standard AM signal with the above requirements, the formula is:
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$$ s(t) = (1+A \cos(2\pi f_{LF}t)) \cdot \cos(2\pi f_{VF} t)$$
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With the power of a wave signal given by $P=\frac{(v_m/\sqrt{2})^2}{2}$ (where $v_m$ is max of cosine signal),
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our sideband power is $2* \frac{(A/\sqrt{2})^2}{2} = \frac{A^2}{2}$
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and our carrier power $\frac{1}{2}$, equal to the power gained in DSB-SC.
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# Time Synchronization
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Time sync between sender and receiver is important because the carrier wave has to be used to demodulate the signal in the receiver.
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If there is a time shift, there will be a phase error introduced by the demodulation, resulting in a distorted signal.
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